A length of pipe went into service with a measured wall of {t_orig} in ({t_orig_mm} mm). The same location reads {t_now} in ({t_now_mm} mm) after {years} years of continuous service. Compute the long-term corrosion rate.
Answer and explanation
The long-term rate is the whole loss divided by the whole time that produced it, and nothing in the arithmetic is harder than one subtraction and one division. What makes it worth asking is that each wrong option is a different accounting of the same two numbers: one divides by months and files the answer as an annual figure, one forgets that a rate needs a loss rather than a thickness, and one multiplies where it should divide. A rate reported twelve times too small looks entirely reasonable on paper, and the life computed from it will be twelve times too long.
- Option B: divides by the elapsed months while labelling the result an annual rate.
- Option C: divides the surviving wall by the years, which is not a loss at all.
- Option D: multiplies by the years instead of dividing, so the figure grows with time in service.
This question draws new numbers every time it is served. The answer cannot be memorised — only the method transfers.